diff --git a/content/Week_1_6/WS_1_6_solution.ipynb b/content/Week_1_6/WS_1_6_solution.ipynb
index 584f03de31daf0d47b50eabe168b4a66a9609e72..c0cc2c12676f7b1f886298ede56a0b979dd163cb 100644
--- a/content/Week_1_6/WS_1_6_solution.ipynb
+++ b/content/Week_1_6/WS_1_6_solution.ipynb
@@ -144,7 +144,9 @@
    "source": [
     "<div style=\"background-color:#AABAB2; color: black; vertical-align: middle; padding:15px; margin: 10px; border-radius: 10px\">\n",
     "<p>\n",
-    "<b>Task 3.1:</b> The time step of 5 seconds is constant. Discretize the time points, the solution vector $T$ and define the initial condition.\n",
+    "<b>Task 3.1:</b> \n",
+    "\n",
+    "The time step of 5 seconds is constant. Discretize the time points, the solution vector $T$ and define the initial condition.\n",
     " \n",
     "</p>\n",
     "</div>"
@@ -179,7 +181,9 @@
    "source": [
     "<div style=\"background-color:#AABAB2; color: black; vertical-align: middle; padding:15px; margin: 10px; border-radius: 10px\">\n",
     "<p>\n",
-    "<b>Task 3.2:</b> Implement your time discretization and find the solution from $t=0$ until $t=60$ sec. \n",
+    "<b>Task 3.2:</b> \n",
+    "\n",
+    "Implement your time discretization and find the solution from $t=0$ until $t=60$ sec. \n",
     " \n",
     "</p>\n",
     "</div>"
@@ -344,7 +348,7 @@
     "\\frac{d^2T}{dx^2} -\\alpha(T-T_s)=0\n",
     "$$\n",
     "\n",
-    "The ambient temperature is $T_s= 30^o$ C and the temperature at the wall is $250^o$ C. The length of the pint is 0.1m. Your grid should have a spatial step of 0.02 m. Finally, $\\alpha=500$."
+    "The ambient temperature is $T_s= 30^o$ C and the temperature at the wall is $250^o$ C. The length of the pin is 0.1m. Your grid should have a spatial step of 0.02 m. Finally, $\\alpha=500$."
    ]
   },
   {
diff --git a/content/Week_1_6/WS_1_6_student.ipynb b/content/Week_1_6/WS_1_6_student.ipynb
index 56a700a00178501815b1695a2d56280f12beb4f2..834f79aacbf604b9acdfb74d723aea26bfc8da85 100644
--- a/content/Week_1_6/WS_1_6_student.ipynb
+++ b/content/Week_1_6/WS_1_6_student.ipynb
@@ -131,7 +131,9 @@
    "source": [
     "<div style=\"background-color:#AABAB2; color: black; vertical-align: middle; padding:15px; margin: 10px; border-radius: 10px\">\n",
     "<p>\n",
-    "<b>Task 3.1:</b> The time step of 5 seconds is constant. Discretize the time points, the solution vector $T$ and define the initial condition.\n",
+    "<b>Task 3.1:</b> \n",
+    "\n",
+    "The time step of 5 seconds is constant. Discretize the time points, the solution vector $T$ and define the initial condition.\n",
     " \n",
     "</p>\n",
     "</div>"
@@ -166,7 +168,9 @@
    "source": [
     "<div style=\"background-color:#AABAB2; color: black; vertical-align: middle; padding:15px; margin: 10px; border-radius: 10px\">\n",
     "<p>\n",
-    "<b>Task 3.2:</b> Implement your time discretization and find the solution from $t=0$ until $t=60$ sec. \n",
+    "<b>Task 3.2:</b> \n",
+    "\n",
+    "Implement your time discretization and find the solution from $t=0$ until $t=60$ sec. \n",
     " \n",
     "</p>\n",
     "</div>"
@@ -286,7 +290,7 @@
     "\\frac{d^2T}{dx^2} -\\alpha(T-T_s)=0\n",
     "$$\n",
     "\n",
-    "The ambient temperature is $T_s= 30^o$ C and the temperature at the wall is $250^o$ C. The length of the pint is 0.1m. Your grid should have a spatial step of 0.02 m. Finally, $\\alpha=500$."
+    "The ambient temperature is $T_s= 30^o$ C and the temperature at the wall is $250^o$ C. The length of the pin is 0.1m. Your grid should have a spatial step of 0.02 m. Finally, $\\alpha=500$."
    ]
   },
   {